# Tamakoshi Electronics Ltd. has following demand and cost
functions:
P = 2000 – 10 Q
TC = 1000 + 200 Q
It is obvious that the general public is willing to purchase
tickets.
So, compute:
a) Profit Maximization Output, Price, TR and
Maximum Profit.
b) Sales Maximizing Output, Price, Profit and
Maximum TR.
c) Output, Price and TR under profit constraints of
Rs. 79,500.
Solution:
Let us see the information given:
We can find that the demand function is represented by P =
2000 – 10 Q. Similarly, cost function is represented by TC = 1000 + 200 Q
Representation of the abbreviations:
P = Price
Q = quantity
TR = Total Revenue
TC = Total Cost
𝝅 = Total Profit
𝝅 = Total Profit
a) For computation of Profit Maximization Output, Price, TR
and Maximum Profit.
Applying the first order condition:
We have,
On solving this, we get 1800 – 20 Q = 0
Or, Q = 90 units
Where,
= (P
X Q) – TC [since TR = P
X Q]
= (2000 – 10 Q) x Q – (1000 + 200
Q) [putting the respective values
of P and TC from the above functions]
= 2000 Q – 10 Q 2 – 1000 – 200 Q
= 1800 Q – 10 Q2 – 1000……………………………………………equation (i)
Again, under second order condition, we have:
The second order condition is negative,
so as per maxima approach, the profit function is maximized when 90 units of
output is produced.
So, the required information are as
follows:
- Profit Maximization output is 90 units
- Price is Rs 1100 [since, P = 2000 – 10 Q = 2000 – 10 x 90]
- TR is Rs. 99000 [since, P x Q = 1100 x 90]
- Maximum Profit (𝝅) is Rs. 80000 [ since, 1800 Q – 10 Q2 – 1000 = (1800 x 90) – (10 x 90 x 90) – 1000 ]
b.) For computation of Sales Maximizing Output, Price, Profit
and Maximum TR.
Maximum TR = P x Q = (2000 – 10 Q) x Q [since, P = 2000 – 10 Q]
= 2000 Q – 10 Q2
Now computing the first order condition, we get
Or, 2000 – 20 Q = 0
Or, Q = 100 units
This is the level of output where sales
maximizing could be done.
Testing the second order condition:
The second order condition is negative,
so as per maxima approach, the total revenue is maximized when 100 units of
output is produced.
So, the required information are as
follows:
- Sales Maximizing Output is 100 units of output.
- Price is Rs 1000 [since, P = 2000 – 10 Q = 2000 – (10 x 100) ]
- Maximum Profit (𝝅) is Rs. 79000 [since, 1800 Q – 10 Q2 – 1000 = 1800 x 100 – 10 x 100 x 100 – 1000]
- Maximum TR is Rs. 100,000 [since, P x Q = 1000 x 100 ]
Here, the profit constraints is given as Rs
79,500. This implies that, the total profit of Tamakoshi Electronics Ltd must
be Rs.79, 500 or more.
This means:
𝝅 = Rs. 79,500
As we have the value of 𝝅 in equation (i)
We get,
𝝅 = 1800 Q – 10 Q2 – 1000
Or, 79,500
= 1800 Q – 10 Q2 – 1000
[putting the value of 𝝅 as
79,500]
Or, 10 Q2 – 1800 Q +79,500 +
1000 = 0
Or, 10 Q2 – 1800 Q + 80,500 =
0
On solving the above equation we get,
Q = 97 units or 83 units
Now, if Q = 97 units, Then
- P is Rs. 1030 [since, P = 2000 – 10 Q = 2000 – 10 x 97 = 1030]
- TR is Rs. 99910 [since, P x Q = 1030 x 97]
- TC is Rs. 20,400 [since, TC = 1000 + 200 Q = 1000 + (200 x 97) ]
- 𝝅 = Rs. 79,510 [since, TR – TC = 99910 – 20400]
However, if Q = 83 units, Then
- P is Rs. 1170 [since, P = 2000 – 10 Q = 2000 – 10 x 83 = 1030]
- TR is Rs. 97110 [since, P x Q = 1030 x 83]
- TC is Rs. 17600 [since, TC = 1000 + 200 Q = 1000 + (200 x 83) ]
- 𝝅 is Rs. 79,510 [since, TR – TC = 99910 – 20400]
Therefore, the required information are
as follows:
- Output is 97 units
- Price is Rs. 1030
- TR under profit constraints of Rs. 79,500 is Rs. 99910.
Note :
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